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-4t^2+7t+70=0
a = -4; b = 7; c = +70;
Δ = b2-4ac
Δ = 72-4·(-4)·70
Δ = 1169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1169}}{2*-4}=\frac{-7-\sqrt{1169}}{-8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1169}}{2*-4}=\frac{-7+\sqrt{1169}}{-8} $
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